Z^2+7z-12=z^2+3z+8

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Solution for Z^2+7z-12=z^2+3z+8 equation: 



^2+7Z-12=Z^2+3Z+8

We move all terms to the left:

^2+7Z-12-(Z^2+3Z+8)=0

We add all the numbers together, and all the variables

7Z-(Z^2+3Z+8)=0

We get rid of parentheses

-Z^2+7Z-3Z-8=0

We add all the numbers together, and all the variables

-1Z^2+4Z-8=0

a = -1; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-1)·(-8)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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